Tugas Subneting

Buat teman-teman kuhh kelas B. IT siang.... ne ica kasi jawaban subnetting....
silahkan tinggal coppy paste di ms.word... tyuz kirim dech ke email dosen.... oh ya sekedar info ne... karna masih banyak yang cmz ica nannya email dosen... ne dia emailnya... kh.mhdamin@gmail.com
 and now silahkan coppy paste.....


1.  201.187.1.0/ 25  <tidak valid>

Subnetmask 25 : 11111111.11111111.11111111.10000000 = 255.255.255.128

Menghitung subnet:

Jumlah subnet : 2¹ = 2 subnet                                                                          

Jumlah host : 2⁷ - 2 = 128-2= 126 host

Blok subnet : 256 – 128 = 128, block berikutnya 128+128 = 256, 256+128= 384

Jadi blok subnetnya 0, 128, 256, 384

Alamat host broadcast yang valid :

Subnet	201.187.1.0	201.187.1.128	201.187.1.256	201.187.1.384
Host pertama	201.187.1.1	201.187.1.129	201.187.1.257	201.187.1.385
Host terakhir	201.187.1.126	201.187.1.254	201.187.1.382	201.187.1.254
Broadcast	201.187.1.127	201.187.1.255	201.187.1.383	201.187.1.255

L---------TIDAK VALID------- L

2.  192.168.0.0 /26

Subnetmask 26 : 11111111.11111111.11111111.11000000 = 255.255.255.192

Menghitung subnet:

Jumlah subnet : 2² = 4 subnet

Jumlah host : 2⁶ - 2 = 64-2= 62 host

Blok subnet : 256 – 192 = 64, block berikutnya 64+64 = 128, 128 + 64= 192

Jadi blok subnetnya 0, 64, 128,192

Alamat host broadcast yang valid :

Subnet	192.168.0.0	192.168.0.64	192.168.0.128	192.168.0.192
Host pertama	192.168.0.1	192.168.0.65	192.168.0.129	192.168.0.193
Host terakhir	192.168.0.62	192.168.0.126	192.168.0.190	192.168.0.254
Broadcast	192.168.0.63	192.168.0.127	192.168.0.191	192.168.0.255

  

3. 198.178.12.0 /27

Subnetmask 27 : 11111111.11111111.11111111.11100000 = 255.255.255.224

Menghitung subnet:

Jumlah subnet : 2³ = 8 subnet

Jumlah host : 2⁵ - 2 = 32 - 2= 30 host

Blok subnet : 256 – 224 = 32, block berikutnya 32+32 = 64, 64 + 32= 96

Jadi blok subnetnya 0, 32, 64, 96

Alamat host broadcast yang valid :

Subnet	198.178.12.0	198.178.12.32	198.178.12.64	198.178.12.96
Host pertama	198.178.12.1	198.178.12.33	198.178.12.65	198.178.12.97
Host terakhir	198.178.12.30	198.178.12.62	198.178.12.94	198.178.12.254
Broadcast	198.178.12.31	198.178.12.63	198.178.12.95	198.178.12.255

4.  212.168.0.0 /28

Subnetmask 28 : 11111111.11111111.11111111.11110000 = 255.255.255.240

Menghitung subnet:

Jumlah subnet : 2⁴ = 16 subnet

Jumlah host : 2⁴ - 2 = 16 - 2= 14 host

Blok subnet : 256 – 240 = 16, block berikutnya 16+16 = 32,  32 + 16= 48

Jadi blok subnetnya 0, 16, 32, 48

Alamat host broadcast yang valid :

Subnet	212.168.0.0	212.168.0.16	212.168.0.32	212.168.0.48
Host pertama	212.168.0.1	212.168.0.17	212.168.0.33	212.168.0.49
Host terakhir	212.168.0.14	212.168.0.30	212.168.0.46	212.168.0.254
Broadcast	212.168.0.15	212.168.0.31	212.168.0.47	212.168.0.255

5. 195.179.0.0 /29

Subnetmask 29 : 11111111.11111111.11111111.11111000 = 255.255.255.248

Menghitung subnet:

Jumlah subnet : 2⁵ = 32 subnet

Jumlah host : 2³ - 2 = 8 - 2= 6 host

Blok subnet : 256 – 248 = 8, block berikutnya 8+8 = 16,  16 + 8= 24

Jadi blok subnetnya 0, 8, 16, 24

Alamat host broadcast yang valid :

Subnet	195.179.0.0	195.179.0.8	195.179.0.16	195.179.0.24
Host pertama	195.179.0.1	195.179.0.9	195.179.0.17	195.179.0.25
Host terakhir	195.179.0.6	195.179.0.14	195.179.0.22	195.179.0.254
Broadcast	195.179.0.7	195.179.0.15	195.179.0.23	195.179.0.255

6.   221.168.0.0 /30

Subnetmask 30 : 11111111.11111111.11111111.11111100 = 255.255.255.252

Menghitung subnet:

Jumlah subnet : 2⁶ = 64 subnet

Jumlah host : 2² - 2 = 4 - 2= 2 host

Blok subnet : 256 – 252 = 4, block berikutnya 4+4 = 8,  8 + 4= 12

Jadi blok subnetnya 0, 4, 8, 12

Alamat host broadcast yang valid :

Subnet	221.168.0.0	221.168.0.4	221.168.0.8	221.168.0.12
Host pertama	221.168.0.1	221.168.0.5	221.168.0.9	221.168.0.13
Host terakhir	221.168.0.2	221.168.0.6	221.168.0.10	221.168.0.254
Broadcast	221.168.0.3	221.168.0.7	221.168.0.11	221.168.0.255

                                                                                                                          

.:: Selesai::. 


note :  sorry ne bisa ngasi jawabnya baru tadi.... hehehehehe oy... buat IP nya karena dosen cuma ngasi subnetnya jadi IP nya kita karang z, yang penting masih di kelas C...  sekedar info juga IP kelas C itu dari 192 s/d 223.... jadi please IP nya di karang z,,, biar dosen enggak curiga.... oke

.:::angel lovely ploeto::::.